Câu 3: Trang 132 sách giáo khoa (SGK) toán tiếng Anh lớp 4Find x:Tìm x:a)\(x+\frac{4}{5}...

a) Cách 1:
\(x+\frac{4}{5} =\frac{3}{2}\)
\(x = \frac{3}{2} -\frac{4}{5}\)
\(x = \frac{15}{10} -\frac{8}{10}\)
\(x = \frac{7}{10}\)

Cách 2:
\(x+\frac{4}{5} =\frac{3}{2}\)
\(x = \frac{3}{2} - \frac{4}{5}\)
\(x = \frac{15-8}{10}\)
\(x = \frac{7}{10}\)

b) Cách 1:
\(x+\frac{3}{2} =\frac{11}{4}\)
\(x = \frac{11}{4} -\frac{3}{2}\)
\(x = \frac{11}{4} -\frac{6}{4}\)
\(x = \frac{5}{4}\)

Cách 2:
\(x+\frac{3}{2} =\frac{11}{4}\)
\(x = \frac{11-6}{4}\)
\(x = \frac{5}{4}\)

c) Cách 1:
\(\frac{25}{3} -x=\frac{5}{6}\)
\(x= \frac{25}{3} -\frac{5}{6}\)
\(x= \frac{50}{6} -\frac{5}{6}\)
\(x = \frac{45}{6}\)

Cách 2:
\(\frac{25}{3} -x=\frac{5}{6}\)
\(x= \frac{25}{3} -\frac{5}{6}\)
\(x= \frac{50-5}{6}\)
\(x = \frac{45}{6}\)

Vậy,
a) \(x = \frac{7}{10}\)
b) \(x = \frac{5}{4}\)
c) \(x = \frac{45}{6} = \frac{15}{2}\)