Câu 2: Trang 148 sách giáo khoa (SGK) toán tiếng Anh lớp 4Two warehouses contain 125 tons of rice,...

Let a be the number of tons of rice in the first warehouse and b be the number of tons of rice in the second warehouse. We have a + b = 125 and a = (3/2)b. Substitute the second equation into the first equation, we get (3/2)b + b = 125, which simplifies to 5b/2 = 125. Solving for b, we get b = 50. Therefore, the second warehouse contains 50 tons of rice and the first warehouse contains 75 tons of rice.

Let's assume that the first warehouse contains x tons of rice. Then the second warehouse contains (2/3)x tons of rice. The total amount of rice in both warehouses is x + (2/3)x = 125. This gives us the equation 3x/3 + 2x/3 = 125, which simplifies to 5x/3 = 125. Solving for x, we get x = 75. Therefore, the first warehouse contains 75 tons of rice and the second warehouse contains 50 tons of rice.

Let y be the number of tons of rice in the first warehouse. Therefore, the number of tons of rice in the second warehouse is 2y/3. We have y + 2y/3 = 125, which simplifies to 3y + 2y = 375. Solving this equation, we get y = 75. So, the first warehouse contains 75 tons of rice, and the second warehouse contains 50 tons of rice.

Let x be the number of tons of rice in the second warehouse. Therefore, the number of tons of rice in the first warehouse is 3x/2. We have x + 3x/2 = 125, which simplifies to 2x + 3x = 250. Solving this equation, we get x = 50. So, the second warehouse contains 50 tons of rice, and the first warehouse contains 75 tons of rice.