Câu 3: trang 146 - toán tiếng anh lớp 5A motorbike travelled at 8:37 am from A at a speed of 36...

Câu trả lời chi tiết và đầy đủ hơn cho câu hỏi trên như sau:

The time that the motorbike travels but the car does not is:
$11\text{ hours }7\text{ minutes} - 8\text{ hours }37\text{ minutes} = 10\text{ hours }67\text{ minutes} - 8\text{ hours }37\text{ minutes} = 2\text{ hours }30\text{ minutes}$
$= 2\frac{1}{2} \text{ hours} = 2.5\text{ hours}$.

At 11:07, the motorbike travelled a distance:
$s = v \times t = 36 \times 2.5 = 90$ km.

The car, with a speed of 54 km/h, catches up to the motorbike at a rate of 18 km/h (54 - 36) per hour. Therefore, it takes:
$\frac{90}{18} = 5$ hours for the car to catch up.

Adding this time to the initial time of 11 hours 7 minutes gives us the time at which the car catches up with the motorbike:
$11\text{ hours }7\text{ minutes} + 5\text{ hours} = 16\text{ hours }7\text{ minutes}$ (or 4:07 pm).

So, the car catches up with the motorbike at 4 hours 7 minutes pm, or 16 hours 7 minutes.

Đáp số: 16 giờ 7 phút hoặc 4 giờ 7 phút chiều.