Câu 2: trang 170 - toán tiếng anh lớp 5A rectangular parcel has a perimeter of 120m. The length is...

Let W represent the width of the rectangular parcel. Hence, the length is W + 10. The perimeter is 2(W + W + 10) = 120m. By solving for W, we get W = 25. Hence, the width is 25m and the length is 35m. Consequently, the area is 25m x 35m = 875 square meters.

Assume the width of the rectangular parcel is W meters. Therefore, the length is W + 10 meters. The perimeter of the parcel is 2(W + W + 10) = 120m. Simplify the equation to obtain W = 25. Thus, the width is 25m and the length is 35m. The area of the parcel is 25m x 35m = 875 square meters.

Let x be the width of the rectangular parcel. Then, the length is x + 10. The perimeter is 2(x + x + 10) = 120m. Simplifying, we get x + x + 10 = 60. Solving for x, we get x = 25. Thus, the width is 25m and the length is 35m. The area is 25m x 35m = 875 square meters.

Let the width of the rectangular parcel be W meters. Then, the length is W + 10 meters. The perimeter of the parcel is 2(W + W + 10) = 120m. Solving for W, we get W = 25. So, the width is 25m and the length is 35m. The area of the parcel is 25m x 35m = 875 square meters.

Let the width of the rectangular parcel be x meters. Then, the length is x + 10 meters. The perimeter of the parcel is 2(x + x + 10) = 120m. Solving for x, we get x = 25. So, the width is 25m and the length is 35m. The area of the parcel is 25m x 35m = 875 square meters.