Khí CO 2 chiếm 0,03 % thể tích không khí. Thể tích không khí (ở đktc) để cung cấp CO 2 cho phản ứng quang hợp để tạo ra 27 gam glucozơ là: A. 44800 lít B. 672 lít C. 67200 lít   D. 448 lít
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In order to determine the volume of air needed to produce 27 grams of glucose through photosynthesis using CO2, we can use the concept of proportion. Since CO2 constitutes 0.03% of the air volume, the volume of air required can be calculated as follows: (0.03/100) * X = 27 grams, where X represents the volume of air needed. Solving this equation, we find that X = 90,000 liters. Therefore, the volume of air required is 90,000 liters.

Given that the percentage of CO2 in air is 0.03%, we can calculate the volume of air required for the production of 27 grams of glucose. Let's assume that the volume of air needed is X liters. Therefore, the volume of CO2 in X liters of air would be 0.03% of X. Setting up the equation, we have: (0.03/100) * X = 27 grams. Solving this equation, we find that X = 90,000 liters. Hence, the volume of air required is 90,000 liters.

To calculate the volume of air required to produce 27 grams of glucose through photosynthesis using CO2, we can use the concept of proportional relationship. Since CO2 occupies 0.03% of the air volume, therefore, the volume of air needed would be (100/0.03) times the volume of CO2. Hence, the volume of air required is (100/0.03) * 27 grams = 90,000 liters.

The percentage of CO2 in air is 0.03%. To create 27 grams of glucose through photosynthesis, we need to calculate the volume of air required. Let's assume that the total volume of air needed is X liters. Therefore, the volume of CO2 in X liters of air would be 0.03% of X. Based on the given information, the equation is: 0.03% of X = 27 grams. Solving this equation, we find that X = 90,000 liters. Therefore, the volume of air required is 90,000 liters.