Bài 1: a) (-1,25)+17,55+(-3,5)-(-2,45) b)\(\left(\dfrac{-5}{9}.\dfrac{11}{4}+\dfrac{-4}{9}.\dfrac{11}{4}\right).\dfrac{88}{3}\) c)\(\left(\dfrac{-9}{25}\right).\dfrac{53}{5}-\left(\dfrac{-3}{5}\right)^2.\dfrac{22}{5}\)
Uh oh, mình đang rối bời với một câu hỏi khó đây. Mọi người có thể giúp mình tìm câu trả lời được không?

a: \(\left(-1,25\right)+17,55+\left(-3,5\right)-\left(-2,45\right)\)

\(=-1,25+17,55-3,5+2,45\)

\(=\left(-1,25-3,5\right)+\left(17,55+2,45\right)\)

\(=-4,75+20=15.25\)

b: \(\left(-\dfrac{5}{9}\cdot\dfrac{11}{4}+\dfrac{-4}{9}\cdot\dfrac{11}{4}\right)\cdot\dfrac{88}{3}\)

\(=\dfrac{11}{14}\left(-\dfrac{5}{9}-\dfrac{4}{9}\right)\cdot\dfrac{88}{3}\)

\(=-\dfrac{11}{14}\cdot\dfrac{88}{3}=\dfrac{-11\cdot44}{7\cdot3}=\dfrac{-484}{21}\)

c: \(\left(-\dfrac{9}{25}\right)\cdot\dfrac{53}{5}-\left(-\dfrac{3}{5}\right)^2\cdot\dfrac{22}{5}\)

\(=\dfrac{9}{25}\cdot\dfrac{-53}{5}-\dfrac{9}{25}\cdot\dfrac{22}{5}\)

\(=\dfrac{9}{25}\left(-\dfrac{53}{5}-\dfrac{22}{5}\right)=\dfrac{9}{25}\cdot\left(-15\right)=-9\cdot\dfrac{3}{5}=-\dfrac{27}{5}\)