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Câu hỏi Hóa học Lớp 12
Câu hỏi Lớp 12
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Phương pháp giải:Bước 1: Xác định số mol chất béo X và các sản phẩm khí CO2, H2O.- Theo đề bài, để đốt cháy hoàn toàn m gam chất béo X cần 3,22 mol O2.- Từ đó, ta suy ra số mol chất béo X là 3,22 mol.- Số mol CO2 được sinh ra là 2,28 mol và số mol H2O được sinh ra là 2,12 mol.Bước 2: Xác định phương trình phản ứng giữa chất béo X và KOH.- Một triglixerit (chất béo) phản ứng với 3 NaOH tạo thành muối natri của các axit béo và 3 CH3OH (rượu metylic).Bước 3: Tính số mol muối tạo thành từ 13,29 gam chất béo X.- Molar tỉ lệ giữa muối và chất béo là 1:1 (vì 1 triglixerit phản ứng với 3 NaOH).- Khối lượng muối tạo thành từ 13,29 gam chất béo X sẽ bằng khối lượng của chất béo X.- Vậy, khối lượng muối tạo thành là 13,29 gam.Câu trả lời: C. 13,71.
The balanced chemical equation for the complete combustion of triglyceride X is:C3H5(XO2)3 + 19O2 -> 12CO2 + 10H2OFrom the equation, it can be calculated that 1 mole of X produces 12 moles of CO2 and 10 moles of H2O.Given that 3,22 mol O2 is required to completely burn m grams of X, and the ratios between the products are constant, we can find the number of moles of X using the ratio between O2 and X. So, 3,22 mol O2 = (3,22 mol O2 / 19 mol O2) * (1 mol X / 12 mol CO2) = 0,1774 mol XSince 13,29 g of X is used in the reaction, we can calculate its molar mass.Molar mass of X = 13,29 g / 0,1774 mol X = 74,8 g/mol Now, let's calculate the masses of CO2 and H2O produced. Mass of CO2 = 2,28 mol CO2 * 44 g/mol CO2 = 100,32 gMass of H2O = 2,12 mol H2O * 18 g/mol H2O = 38,16 gFinally, to find the mass of salt formed, we need to find the remaining mass after subtracting the masses of CO2 and H2O from the initial mass of X.Mass of salt formed = 13,29 g - (100,32 g + 38,16 g) = -125,19 g. Since the mass of the salt formed cannot be negative, something went wrong in the calculations. Please double-check the given data or calculations.
The balanced chemical equation for the complete combustion of triglyceride X is:C3H5(XO2)3 + 19O2 -> 12CO2 + 10H2OFrom the equation, it can be calculated that 1 mole of X produces 12 moles of CO2 and 10 moles of H2O.Given that 3,22 mol O2 is required to completely burn m grams of X, and the ratios between the products are constant, we can find the number of moles of X using the ratio between O2 and X. So, 3,22 mol O2 = (3,22 mol O2 / 19 mol O2) * (1 mol X / 12 mol CO2) = 0,1774 mol XSince 13,29 g of X is used in the reaction, we can calculate its molar mass.Molar mass of X = 13,29 g / 0,1774 mol X = 74,8 g/mol Now, let's calculate the masses of CO2 and H2O produced. Mass of CO2 = 2,28 mol CO2 * 44 g/mol CO2 = 100,32 gMass of H2O = 2,12 mol H2O * 18 g/mol H2O = 38,16 gFinally, to find the mass of salt formed, we need to find the remaining mass after subtracting the masses of CO2 and H2O from the initial mass of X.Mass of salt formed = 13,29 g - (100,32 g + 38,16 g) = -125,19 g. Since the mass of the salt formed cannot be negative, something went wrong in the calculations. Please double-check the given data or calculations.
The balanced chemical equation for the complete combustion of triglyceride X is:C3H5(XO2)3 + 19O2 -> 12CO2 + 10H2OFrom the equation, it can be calculated that 1 mole of X produces 12 moles of CO2 and 10 moles of H2O.Given that 3,22 mol O2 is required to completely burn m grams of X, and the ratios between the products are constant, we can find the number of moles of X using the ratio between O2 and X. So, 3,22 mol O2 = (3,22 mol O2 / 19 mol O2) * (1 mol X / 12 mol CO2) = 0,1774 mol XSince 13,29 g of X is used in the reaction, we can calculate its molar mass.Molar mass of X = 13,29 g / 0,1774 mol X = 74,8 g/mol Now, let's calculate the masses of CO2 and H2O produced. Mass of CO2 = 2,28 mol CO2 * 44 g/mol CO2 = 100,32 gMass of H2O = 2,12 mol H2O * 18 g/mol H2O = 38,16 gFinally, to find the mass of salt formed, we need to find the remaining mass after subtracting the masses of CO2 and H2O from the initial mass of X.Mass of salt formed = 13,29 g - (100,32 g + 38,16 g) = -125,19 g. Since the mass of the salt formed cannot be negative, something went wrong in the calculations. Please double-check the given data or calculations.