\(a,30\%.x-x+\dfrac{4}{3}\) \(b,\dfrac{1}{6}-\dfrac{1}{3}\left(x-\dfrac{1}{2}\right)^2=\dfrac{-1}{6}\) \(c,\dfrac{3}{8}-\left(x+2\right)^3=\dfrac{1}{2}\)

a: Đề thiếu vế phải rồi bạn

b: \(\dfrac{1}{6}-\dfrac{1}{3}\left(x-\dfrac{1}{2}\right)^2=-\dfrac{1}{6}\)

=>\(\dfrac{1}{3}\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{6}+\dfrac{1}{6}=\dfrac{2}{6}=\dfrac{1}{3}\)

=>\(\left(x-\dfrac{1}{2}\right)^2=1\)

=>\(\left[{}\begin{matrix}x-\dfrac{1}{2}=1\\x-\dfrac{1}{2}=-1\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{1}{2}\end{matrix}\right.\)

c: \(\dfrac{3}{8}-\left(x+2\right)^3=\dfrac{1}{2}\)

=>\(\left(x+2\right)^3=\dfrac{3}{8}-\dfrac{1}{2}=-\dfrac{1}{8}\)

=>\(x+2=-\dfrac{1}{2}\)

=>\(x=-\dfrac{1}{2}-2=-\dfrac{5}{2}\)

Hãy giúp mọi người biết câu trả lời này thế nào?

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